The limit in the given graph 
is 3 and 
is -2
Given graph of a function and we have to determine the limits when x tends to 2 minus and when x tends to 2 plus.
When we see the graph we can find that the graph is not of the linear function because it is not straight line.
From x=2 and onwards it gives values values of only -2 because it is parallel to x-axis at y=-2.From x=2 and leftwards it gives values values of only 3 because it is parallel to x-axis at y=3.
Hence the limit of the function whose graph is shown is 3 and -2.
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Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
65
Step-by-step explanation:
2w+ 2l = 300
2w + 170=300
2w= 130
w=65
-5(a + 3) = -55
(a + 3)(-5) = -55
(a + 3) (-5)/-5 = -55/ (-5)
a + 3 = 11
a + 3 (-3) = 11 (-3)
a = 8
hope this helps
Answer:
Step-by-step explanation:
Refer to the figure and match the theorem that supports the statement.
1. If chords are =, then arcs are =.
If BC = DE, then Arc BC = Arc DE
2. If arcs are =, then chords are =.
If Arc BC = Arc DE, then BC = DE
3. Diameters perpendicular to chords bisect the chord
If AX is perpendicular to BC, then BX = XC
