Answer:
The future value is: RS 132867.075
Step-by-step explanation:
Given
--- present value
--- annual rate
--- number of times compounded (3 years/ 6 months)
Required
The future value
This is calculated as:
<em>Hence, the future value is: RS 132867.075</em>
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Since adding a constant to a function simply moved the graph upwards by that amount, solve f(x) for any value and see how much the graph given is different from that value of y...the simplest way in this case may be to simply find f(0) which is:
5*2^0=5
Clearly the graph at x=0 is at y=-2 so we can see that k is:
5+k=-2 so
k=-7
Answer:
How bout no-_-
Step-by-step explanation:
You not smart
