How far above the ground is a 3,000 kg airplane
1 answer:
The altitude of the plane is 32.6 m
Explanation:
The gravitational potential energy of an object is the energy possessed by the object due to its position in a gravitational field.
Near the Earth's surface, the potential energy of an object is given by:
where
m is the mass of the object
g is the acceleration of gravity
h is the height of the object above the ground
For the plane in this problem, we know that:
is the potential energy
m = 3,000 kg is the mass
Solving for h, we find the altitude of the plane:
Learn more about gravitational potential energy:
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(a) 12.8 kg m/s
The impulse delivered by the bat on the baseball is equal to the change in momentum of the baseball:
where we have
m = 0.144 kg is the mass of the ball
v = -47 m/s is the final velocity of the ball
u = 42 m/s is the initial velocity of the ball
Substituting into the equation, we find
And since we are interested in the magnitude only,
(b) 2.78 kN
The impulse exerted on the ball is also equal to the product between the average force and the contact time:
where
F is the average force exerted on the ball
is the contact time
Solving the formula for F, we find
(c) The force exerted on the ball is much larger (1988 times more) than the weigth of the ball
The weight of the ball is given by
where
m = 0.144 kg is the mass of the ball
g = 9.8 m/s^2 is the acceleration due to gravity
Solving the equation for W, we find
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