Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
Answer:
Acceleration = Passing a car on the highway/Any change in speed or direction/Slowing down to turn at an intersection
Friction = The force that opposes motion/The wheels moving against the road
Newton's first law = An object in motion stays in motion unless acted on by an outside force
Newton's second law = The harder you kick a ball the faster it will travel
Answer:
Look below
Explanation:
Units are very important. Let's say we were building an apartment. We used meters for every measurement except for 1 support where we used centimeters. This could lead to the collapse of the whole structure as the measurements were wrong. 100 meters and 100 centimeters are very different.
The average dissipated power in a resistor in a ac circuit is:
where R is the resistance, and
is the root mean square current, defined as
where
is the peak value of the current. Substituting the second formula into the first one, we find
and if we re-arrange this formula and use the data of the problem, we can find the value of the peak current I0:
Answer:
4.0 m/s²
Explanation:
Draw two free body diagrams, one for the cart and one for the hanging mass.
The cart has one force acting on it in the x direction: tension to the right.
The hanging mass has two forces acting on it in the y direction: tension up and weight down.
The hanging mass accelerates downward, so if we take up to be positive, then the acceleration is negative.
Apply Newton's second law to the hanging mass:
∑F = ma
T − m₂g = m₂(-a)
T − m₂g = -m₂a
Apply Newton's second law to the cart:
∑F = ma
T = m₁a
Substitute and solve for a:
m₁a − m₂g = -m₂a
m₁a + m₂a = m₂g
(m₁ + m₂) a = m₂g
a = m₂g / (m₁ + m₂)
Given m₁ = 2.3 kg and m₂ = 1.6 kg:
a = (1.6 kg × 9.8 m/s²) / (2.3 kg + 1.6 kg)
a = 4.0 m/s²
