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Talja [164]
2 years ago
6

At a certain instant a rigid wheel is spinning about its center of mass with angular velocity of magnitude ω and angular acceler

ation of magnitude α. Consider a point a distance r from the axis of rotation. What would be the magnitude of the acceleration of this point on the wheel?
Physics
1 answer:
geniusboy [140]2 years ago
7 0

Answer:

a = r√(w⁴ + (alpha)²)

Explanation:

let w be the magnitude of angular velocity

r = radius

v = velocity = wr

angular acceleration, ā = v²/r = (wr)²/r = w²r

Also,

â = dv/dt = rdw/dt

given : alpha = dw/dt

hence, â = (alpha)r

the resultant acceleration, a, by Pythagoras is given as

a = √( â² + ā²) = √(r²w⁴ + r²(alpha)²)

simplifying,

a = √r²(w⁴ + (alpha)²)

a = r√(w⁴ + (alpha)²)

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Calculate the net force and the acceleration on the block
Darina [25.2K]

Answer:

Net Force = 10N

Acceleration = 2m/s^2

Explanation:

calculate the net force and the acceleration on the block

Net force on the block F = mass * acceleration

Net force acting in the positive direction = 4N + 6N = 10N

Mass = 5kg

According to newton's second law;

a = F/m

a = 10N/5

a = 2m/s^2

hence the acceleration on the block is 2m/s^2

7 0
3 years ago
URGENT!! HELP
Monica [59]

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8 0
2 years ago
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A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does
alina1380 [7]

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is  1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| =  1x10⁻⁶/9800

|Q| =  1.02 x 10⁻⁹ Coulomb

c) No of electrons  = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

6 0
2 years ago
A pilot wants to fly on a bearing of 74.9 degrees. By flying due east, he find s that a 42-mph wind, blowin from the south, puts
hichkok12 [17]
The bearing shows the angle from north to the line (c), you want to see the angle inside the triangle so that will be 90-[bearing]. 

<span>a=42 (42 mph wind blowing north) </span>

<span>A= 90-74.9 </span>
<span>A= 15.1 degrees </span>

<span>Ground speed is the speed the plane is going including the wind. </span>
<span>ground speed = c </span>
<span>Airspeed = b </span>

<span>You have the angle, and you have the "Opposite" and want to find the "Hypotenuse". </span>
<span>SOH CAH TOA </span>

<span>Sin x = Opp/Hypot </span>

<span>Sin(15.1) = 42/c </span>
<span>c = 42/Sin(15.1) </span>
<span>c = 161.53 </span>

<span>Ground speed of the plane is 161.53 mph </span>

<span>Airspeed = b </span>

<span>Tan x = Opp/Adj </span>
<span>Tan (15.1) = 42/b </span>
<span>b = 42/Tan(15.1) </span>
<span>b = 161.53 </span>

<span>Airspeed = 161.53 mph </span>

<span>(so the answer is ground speed of 161.53mph)</span>
3 0
3 years ago
Trata de que bobo 1 2 3
kkurt [141]

Answer:

what?

Explanation:

3 0
3 years ago
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