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2 years ago

12

There were 600 soldiers in battle. The ratio of Texas soldiers to Mexican soldiers was 7 to 3, how many more Texan soldiers were

in the battle?

1 answer:

nevsk [136]2 years ago

8 0

257

.................

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X^2-7x-6=0<br> Use the quadratic formula to complete the equation show step by step

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x = 7 ± √73 / 2

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An underhand serve follows the same parabolic path but is hit from a height of 3 feet. How will this affect the focus and direct

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a rhombus can be cut in half by a diagonal to make two isosceles triangle correct or incorrect if incorrect give an example to s

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3 years ago

on jan 22 0217 the cost to mail a letter in the us was raised from 47 to 49 centrs. find the relative change in the cost

Nikolay [14]

The relative change is 2%.

<h3>What is relative change?</h3>

In contrast to the reference value, the absolute change's size is expressed as a fraction called the relative change: relative change = absolute change reference value = new value reference value reference value. The absolute change is expressed as a percentage of the value of the indicator in the prior period, or "relative change" expresses the absolute change as such. When measuring indicators in percentage terms, such as the unemployment rate, absolute and relative change principles also apply. To determine the absolute change, subtract the starting value from the ending value. Simply deduct 1,000 from 1,100 to arrive at 100 in the example. The student population increased by 100 pupils throughout the course of the year because this is the absolute change.

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1 year ago

Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the

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The average travel time is simply the mean travel time between the given points

The average time that it takes for the car to travel the first 0.25m is 2.23s.
The average time to travel just between 0.25m and 0.50m is 0.9s.
Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

<u>(a) The average time to travel the first 0.25m</u>

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

$Time = \frac{2.24s + 2.21s + 2.23s}{3}$

$Time = \frac{6.68s}{3}$

$Time = 2.23s$

<u>(b) The average time to travel just between 0.25m and 0.50m</u>

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

$Time = \frac{3.16s + 3.08s + 3.15s}{3}$

$Time = \frac{9.39s}{3}$

$Time = 3.13s$

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

$Average = 3.13s - 2.23s$

$Average = 0.9s$

<u>(c) The velocity in the second 0.25m section</u>

The distance and time are:

$Distance = 0.25m$

$Time = 0.9s$

So, the velocity is:

$Velocity = \frac{Distance}{Time}$

This gives

$Velocity = \frac{0.25m}{0.9s}$

$Velocity = 0.28m/s$

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2 years ago