Answer:
13 and 14.
Step-by-step explanation:
So we have two consecutive integers.
Let's call the first integer a.
Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).
We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:
The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.
Solve for a. Combine like terms:
Subtract 1 from both sides. The 1s on the left cancel:
Divide both sides by 3:
Therefore, a or the first integer is 13.
And the second integer is 14.
And we can check:
14+2(13)=14+26=40
Answer:
B y = -.001x +100
Step-by-step explanation:
(0,100) (2000,98)
98-100/ 2000-0 = -2/2000 = -1/1000
y-100 = -.001(x -0)
y= -.001x +100
Answer:
$196
Step-by-step explanation:
Lets assume,
cost of a belt = 'x'
cost of a pair of pants = 'y'
Now, According to the question;
- x + y = 490;
- cost of a bag = twice the cost of belt = 2x;
- cost of a pair of pants = twice the cost of bag
⇒ y = 2×2x ⇔ 4x
hence, by subtituting the values in equation' we get;
⇒ x + 4x = 490
⇒ 5x = 490
⇒ x = 98
So, the difference between the cost of the pair of pants and the bag ;
⇒ y - 2x
⇒ 4x - 2x
⇒ 2x = 2×98 = 196.
Answer:
It’s 60miles
Step-by-step explanation:
We assume the trip is "d" miles and that the "extra hour" refers to the additional time that a current of 2 mph would add. That is, we assume the reference time is for a current of 0 mph.
The time with no current is ...
time1 = distance/speed
time1 = d/12 . . . . hours
With a current of 2 mph in the opposite direction, the time is ...
time2 = d/(12 -2) = d/10
The second time is 1 hour longer than the first, so we have ...
time2 = 1 + time1
d/10 = 1 + d/12
6d = 60 + 5d . . . . multiply by 60
d = 60 . . . . . . . . . subtract 5d
The one-way distance is 60 miles.
