Question

Calculate the average travel time for each distance, and then use the results to calculate. A 6-column table with 3 rows in the second, third, and fifth columns and 1 row in the other columns. The first column labeled Number of Washers has entry 1 washer mass = 4. 9 grams. The second column labeled Trial has entries trial number 1, trial number 2, trial number 3. The third and fourth columns labeled Time to travel 0. 25 meters t subscript 1 (seconds) have entries in the third column 2. 24, 2. 21, 2. 23 and average in the fourth column. The fifth and sixth columns labeled time to travel 0. 5 meters t subscript 2 (seconds) have entries in the fifth column 3. 16, 3. 08, 03. 15 and in the sixth column average. The average time that it takes for the car to travel the first 0. 25m is s. The average time to travel just between 0. 25 m and 0. 50 m is s. Given the time taken to travel the second 0. 25 m section, the velocity would be m/s.

Answer 1

The average travel time is simply the mean travel time between the given points

• The average time that it takes for the car to travel the first 0.25m is 2.23s.
• The average time to travel just between 0.25m and 0.50m is 0.9s.
• Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.

(a) The average time to travel the first 0.25m

The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.

So, the average time to travel is:

$Time = \frac{2.24s + 2.21s + 2.23s}{3}$

$Time = \frac{6.68s}{3}$

$Time = 2.23s$

(b) The average time to travel just between 0.25m and 0.50m

The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.

So, the average time to travel this distance is:

$Time = \frac{3.16s + 3.08s + 3.15s}{3}$

$Time = \frac{9.39s}{3}$

$Time = 3.13s$

The average time to travel between both distance is the difference between the average time of each distance.

So, we have:

$Average = 3.13s - 2.23s$

$Average = 0.9s$

(c) The velocity in the second 0.25m section

The distance and time are:

$Distance = 0.25m$

$Time = 0.9s$

So, the velocity is:

$Velocity = \frac{Distance}{Time}$

This gives

$Velocity = \frac{0.25m}{0.9s}$

$Velocity = 0.28m/s$

Read more about distance, velocity and time at:

brainly.com/question/4931057