Answer:
So it will take 15 year from 1998 to reach population 229 thousands.
i.e. In 2013 population will be 229 thousand.
Step-by-step explanation:
Given:
Formula model population for city A=146e0.03t
To Find:
Years required to reach population 229 thousands after 1998
Solution:
Using the model ,
A=146e0.03t
here A=229
So equation becomes,
229=146e0.03t
(229/146)=e0.03t
Using log function with base 10 on both sides we get ,
Log(229/146)=log(e^0.03t)
log(1.56489)=0.03tlog(e) .................(using log property log(a^n)=nloga)
0.19548=0.03*t*0.43429
0.19548/0.013028=t
t=(0.19548/0.013028)
t=15.01
t=15 years
So it will take 15 year from 1998 to reach population 229 thousands.
Answer: 1.
Step-by-step explanation: 1^5 is really just 1, 5 times.
1*1*1*1*=1
I would say B sorry if im wrong tho
Answer:
8750
Explanation:
There are 5/5 math teachers in the university. 3/5 of them did not want to become math teachers which means 2/5 of the math teachers is equal to 3500.
3500=2/5
divide 3500 by 2 to get 1/5 of the math teachers.
3550/2=1750
1750 is 1/5 of the math teachers.
multiply 1750 by 5 to get 5/5 of the math teachers
1750*5= 8750