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3 years ago

suppose a circle with center (1,-3) passes through point (1,-1). Which equation represents the circle ?

Mathematics

2 answers:

NikAS [45]3 years ago

6 0

Answer:

The answer is C) (x − 1)^2 + (y + 3)^2 = 4

Step-by-step explanation:

The radius is the distance between the center and the point on the circle.

Center: (1, −3); Point: (1, −1)

Distance formula: d = square root of {(x2 - x1)^2 + (y2 - y1)^2}

r = square root of {(1 − 1)^2 + (−1 + 3)^2 }

r = square root of {0 + 4 } = 2

(x − h)^2 + (y − k)^2 = r2 ----> (x − 1)^2 + (y + 3)^2 = 4

Hope this isn't confusing and helps. I also know its right because I just did this on USA Testprep.

horsena [70]3 years ago

4 0

Answer:-4

Step-by-step explanation:

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4 years ago

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Answer:

a) The 90% confidence interval for the mean noise level at such locations

(112.46 , 163.54)

b) The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

Step-by-step explanation:

Step(i) :-

Noise levels at 3 airports were measured in decibels yielding the following data

108 146 160

Mean of given data

$x^{-} = \frac{108+146+160}{3} = 138$

x : 108 146 160

x-x⁻ : -30 8 22

(x-x⁻ )² : 900 64 484

Variance σ ² = ∑(x-x⁻ )²/ n-1

= $\frac{900+64+484}{3-1}= 724$

Standard deviation

σ = √724 = 26.90

Step(ii):-

The 90% confidence interval for the mean noise level at such locations

$(x^{-} - Z_{0.90} \frac{S.D}{\sqrt{n} } , (x^{-} + Z_{0.90} \frac{S.D}{\sqrt{n} } )$

The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

$(138 - 1.645 \frac{26.90}{\sqrt{3} } , (138 + 1.645 \frac{26.90}{\sqrt{3} } )$

( 138 - 25.54 , 138 + 25.54 )

(112.46 , 163.54)

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