Sin2x=2sinxcosx, cos2x=1-2sin^2x
sin(2x)+cos(3x)=2sinxcosx+cos(x+2x)
cos(x+2x)=cosx(1-2sin^2(x))-sinx2sinxcosx
sin(2x)+cos(3x)=2sinxcosx(1-sinx)+cosx(1-2sin^2(x))
Answer:
Area pf the regular pentagon is 193
to the nearest whole number
Step-by-step explanation:
In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter
Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;
Area of regular pentagon = 1/2 × apothem × perimeter
From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches
We plug these values into the equation above to get;
Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193
to the nearest whole number
- line CD is perpendicular to segment AB
- point M is the midpoint of segment AB
Answer:
5
Step-by-step explanation:
The height of the largest triangle = √(9 * 25) = 3 * 5 = 15
y is the square root of (25^2 + 15^2)
y = √(625 + 225)
y = √850
y = √(2 * 5*5 * 17)
y = 5 * √34
5 goes in the box.