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andrey2020 [161]
3 years ago
8

There are 10 boys and 8 girls in the chess club at West Middle School. The principal randomly selects one student from the chess

club to represent the school in a competition. What is the probability that the selected student is a boy?​
Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

5/9 of a chance

Step-by-step explanation:

or a 55.55- chance

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Isaiah decides to launch a model rocket to demonstrate parabolic motion. Given x stands for time and y stands for height in feet
mina [271]

The parabolic motion is an illustration of a quadratic function

The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31

<h3>How to model the function?</h3>

Given that:

x stands for time and y stands for height in feet

So, we have the following coordinate points

(x,y) = (5,0), (11,0) and (10,80)

A parabolic motion is represented as:

y =ax^2 + bx + c

At (5,0), we have:

25a + 5b + c = 0

c= -25a - 5b

At (11,0), we have:

121a + 11b + c = 0

Substitute c= -25a - 5b

121a + 11b -25a - 5b = 0

Simpify

96a + 6b = 0

At (10,80), we have:

100a + 10b + c = 80

Substitute c= -25a - 5b

100a + 10b - 25a -5b = 80

75a -5b = 80

Divide through by 5

15a -b = 16

Make b the subject

b = 15a + 16

Substitute b = 15a + 16 in 96a + 6b = 0

96a + 6(15a + 16) = 0

Expand

96a + 90a + 96 = 0

This gives

186a = -96

Solve for a

a = -16/31

Recall that:

b = 15a + 16

So, we have:

b = -15 * 16/31 + 16

b =-240/31 + 16

Take LCM

b =(-240 + 31 * 16)/31

[tex]b =256/31

Also, we have:

c= -25a - 5b

This gives

c= 25*16/31 - 5 * 256/31

Take LCM

c= -880/31

Recall that:

y =ax^2 + bx + c

This gives

y = -16/31x^2 + 256/31x - 880/31

Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31

Read more about parabolic motion at:

brainly.com/question/1130127

7 0
2 years ago
Simply the following 2m⁵×5m³×7m²​
Ganezh [65]

Answer:

2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}

Step-by-step explanation:

Simplify the expression

2m^5\cdot 5m^3\cdot 7m^2

Calculate the product of the coefficients:

2*5*7=70

Compute the product of the variables. Since they are all the same letter, sum their exponents:

m^5\cdot m^3\cdot m^2=m^{5+3+2}=m^{10}

Combine the results:

\boxed{2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}}

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3 years ago
Xa farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the ba
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Width=34.2
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What is the radian measure of 210 angle 
Gnesinka [82]
The answer is 3.66519.
8 0
3 years ago
Someone help please i am so bad at point slope stuff
Fynjy0 [20]
<span>1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x

2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1). 
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69

3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line. 

4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2

5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2

6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4)  / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7


7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11

</span>
3 0
3 years ago
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