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never [62]
3 years ago
5

I need help bbbbbbbbbbbbbbad Vvvvvv

Mathematics
1 answer:
True [87]3 years ago
8 0

Answer:

\dfrac{5x^2-3x+8}{2x+1}

Step-by-step explanation:

The denominators are the same, so the numerators can be added in the usual way.

... = ((5x^2 +6) -(3x -2))/(2x +1)

... = (5x^2 +6 -3x +2)/(2x +1)

... = (5x^2 -3x +8)/(2x +1)

The numerator and denominator have no common factors, so this cannot be reduced further.

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An oval track is made by erecting semicircles on each end of a 60m by 120m rectangle. Find the length of the track and the area
vodomira [7]
Refer to the figure shown below.

Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.

The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m

The area of the oval is 
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²

Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²

Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²

if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²


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Step-by-step explanation:

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