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3 years ago

What is the value of p in the equation? One-fourth (8 minus 4 p) + 2 p = 12

Mathematics

2 answers:

Tom [10]3 years ago

6 0

P is equal to 10

How to get your answer:

So 1/4(8-4p) + 2p = 12

First you need to distributive by multiplying 1/4 to each term like this:

2 - p + 2p =12

Then you have to combine to terms just as I did below:

2 + p = 12

Then you need to subtract 2 from both sides to get 10 so:

P = 10

ozzi3 years ago

3 0

1/4(8-4p) + 2p = 12

Use distributive property by multiplying 1/4 by each term inside parentheses:

2 - p + 2p =12

Combine like terms:

2 + p = 12

Subtract 2 from both sides:

P = 10

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3 years ago

Read 2 more answers

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DerKrebs [107]

a. Parameterize $C$ by

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with $0\le t\le1$ .

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$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

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d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

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