Answer: The first table
Step-by-step explanation:
1:16
2:32
4:64
8:128
The graph of csc(x) = 1/sin(x) has asymptotes at the points where sin(x) = 0, which happens for x = 2nπ and x = (2n + 1)π, where n is any integer.
This means
• f(x) = 2 csc(x) has the same asymptotes, at x = 2nπ and x = π + 2nπ
• g(x) = 4 csc(2x) has asymptotes at 2x = 2nπ and 2x = π + 2nπ, or equivalently x = nπ and x = π/2 + nπ
• h(x) = 4 csc(3x) has asymptotes at 3x = 2nπ and 3x = π + 2nπ, or x = 2nπ/3 and x = π/3 + 2nπ/3
• j(x) = 2 csc(x/2) has asymptotes at x/2 = 2nπ and x/2 = n + 2nπ, or x = 4nπ and x = 2π + 4nπ
so none of these choices are correct.
Answer:
nzjjxkzjxkxnxkkxxkxbzkzhzzjskzjzjxjknxkxk