The least possible height is the height of the cylinder when the volume is 324π cubic inches. To determine that height, we use the formula for the volume of a cylinder. We do as follows:
Volume = πr^2h
324π = π(6)^2(h)
h = 9 inches
Answer:
d = 6+sqrt(42)=12.4807407
Step-by-step explanation:
h= -d² + 12d + 6
The ball is caught at ground level which means h=0
0 = -d² + 12d + 6
Subtract 6 from each side
-6 = -d^2 +12d
Factor out a - sign
-6 =-(d^2-12d)
Divide by -1
6 = d^2 -12 d
Complete the square
-12/2 = -6 then square it = 36
Add 36 to each side
6+36 = d^2 -12d +36
42 = (d-6)^2
Take the square root of each side
±sqrt(42) = sqrt( (d-6)^2)
±sqrt(42) = (d-6)
Add 6 to each side
6±sqrt(42) = (d-6)+6
6±sqrt(42) = d
d = 6+sqrt(42)=12.4807407
d =6- sqrt(42)=-.480740698
Since the distance cannot be negative
Answer:
73% of 13% which can also be depicted of .73*.13 which is .0949 which could also be 9.5%
Step-by-step explanation:
Answer:
(a)z=-1
(b)48.5 pounds
(c)61.5 pounds
Step-by-step explanation:

Given:
Mean, μ = 55 pounds
Standard deviation,σ = 6 pounds.
(a)For a dog that weighs 49 pounds.
x=49 pounds
The z-score

(b)When a dog has a z-score of -1.09

The weight of a dog with a z-score of -1.09 is 48.5 pounds.
(c)When a dog has a z-score of 1.09

The weight of a dog with a z-score of 1.09 is 61.5 pounds.
Cot(theta) is the one that works best for this problem