A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen
t bacteria grows at a rate of y=3t^2+t+300. In both of these eqiations y is the number of bacteria after t minutes. When is there an equal number of both types of bacteria.
The answer is 7 because 2 times 6 equals 12 + 26 - 12 equals 14 + 14 divided by 2 equals 7 this is how I see you it out the answer again the answer is seven feet feet