Can calculating area under curve expand to calculate volume of sphere

1 answer:

6 0

This is an application of integral calculus. The area under a curve could be expanded to determine the volume of a sphere if you revolve this area about a certain axis or a certain line. It should be given that the area is in the shape of either a half-circle or a quarter circle, so that it should form a sphere when revolved.

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I need help on this please

AnnZ [28]

Answer:

Balblair! op opopopopoop

5 0

2 years ago

What would answer be t -3x + 6 + 12 y

Evgesh-ka [11]

-3x + 6 + 12 y. I am afraid that there are no like terms to combine, and it is neither an equation nor an inequality.

Hope this Helps!

8 0

2 years ago

Can any one please help me in this the teacher did not explain this it have to be in the lowest term also no decimal answer than

Zinaida [17]

Answer:

Step-by-step explanation:

$A . -5+3x =-41\\3x=-41+5\\3x = -36\\\frac{3x}{3} =\frac{-36}{3} \\x = -12\\\\\\\\\\B. 7x-4=-2x+11\\Collect-like-terms\\7x+2x=11+4\\9x=15\\\frac{9x}{9} =\frac{15}{9} \\\\x = \frac{5}{3} \\\\C. \frac{-4x}{5} =8\\Cross-multiply\\-4x=40\\\frac{-4x}{4} =\frac{40}{-4} \\x = -10\\\\D. \frac{x}{3} -\frac{1}{2} =\frac{1}{4} \\\frac{x}{3} =1/4+1/2\\\frac{x}{3} = \frac{3}{4} \\Cross-multiply\\4x =9\\4x/4 =9/4\\x = 9/4\\$

$E . -4(6x+1)+3 =11+2(x+2)\\-24x-4+3=11+2x+4\\Collect-like-terms\\-24x-2x=11+4+4-3\\-26x =16\\\frac{-26x}{-26} =\frac{16}{-26}\\ x = -\frac{8}{13}$

7 0

2 years ago

Help!! will give brainliest

Basile [38]

Answer: 90° counterclockwise rotation about the origin

Step-by-step explanation: Coordinates..

green:

A(-9, 5)

B(-4, 5)

C(-5, -3)

D(-8, -3)

red:

A(5, 9)

B(5, 4)

C(-3, 5)

D(-3, 8)

4 0

2 years ago

Round 34.4567 to the nearest cent

MariettaO [177]

Because 34.4567 is closer to 34.46 than to 34.45, so the answer is 34.46.

3 0

2 years ago