All categories

2 years ago

Can calculating area under curve expand to calculate volume of sphere

1 answer:

6 0

This is an application of integral calculus. The area under a curve could be expanded to determine the volume of a sphere if you revolve this area about a certain axis or a certain line. It should be given that the area is in the shape of either a half-circle or a quarter circle, so that it should form a sphere when revolved.

You might be interested in

Find the EXACT distance between the two points.<br><br><br><br> (4,7) and (−4,9)

bazaltina [42]

ANSWER: $y=-\frac{3}{4} x +6 3x=24-4y$

Ok done. Thank to me :>

6 0

2 years ago

I need a step by step instruction please

Alika [10]

Answer: $x=52$

Step-by-step explanation:

$x-45+45=7+45\\x=52$

3 0

2 years ago

Can you help me to create a histogram graph with the following data please?

AlekseyPX

The attached graph represents a histogram that has a range of 55

<h3>How to create the histogram?</h3>

The range is given as:

Range = 55

The range is calculated as:

Range = Maximum - Minimum

So, we have:

Maximum - Minimum = 55

Rewrite as:

Maximum = Minimum + 55

Let the minimum be 10.

So, we have:

Maximum = 10 + 55

Evaluate

Maximum = 65

The following dataset can be used to create the histogram

Score Frequency

10 2

15 5

45 3

65 1

This is so because it has a range of 55

See attachment for the histogram

Read more about histogram at:

brainly.com/question/14421716

#SPJ1

7 0

1 year ago

Why is the square root of 144 rational

Vitek1552 [10]

The square root of 144= 12. 12 is an integer, integers are always rational since they can be written into a fraction.

7 0

2 years ago

Use the Polygon tool to draw the image of the given quadrilateral under a dilation with a scale

Nataly [62]

Answer: See the picture attached.

Step-by-step explanation:

A Dilation is defined as a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1, the image obtained after the dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

$scale\ factor=\frac{2}{3}$

Since:

$0$

It is a Reduction.

You can identify that the vertices of the quadritaleral are:

$(-3,0),(-9,-3),(-6,-9),(3,-6)$

So you need to multiply the coordinates of eac vertex by $\frac{2}{3}$ in order to get the coordinates of the image.

Then, you get:

$(\frac{(-3)(2)}{3},0*\frac{2}{3})=(-2,0)\\\\(\frac{(-9)(2)}{3}),\frac{(-3)(2)}{3})=(-6,-2)\\\\(\frac{(-6)(2)}{3},\frac{(-9)(2)}{3})=(-4,-6)\\\\(3*\frac{2}{3},\frac{(-6)(2)}{3})=(2,-4)$

Now you can plot the points and draw the image of the given quadrilateral.

See the picture attached.

5 0

3 years ago