All categories

3 years ago

I don't really understand the question so can someone help me answer the question please?

Mathematics

1 answer:

Ksivusya [100]3 years ago

5 0

Answer:

1/ 3

Step-by-step explanation:

If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:

=> P(E) = number of cards of the required type/ total number of cards

● Total number of spades( ♤ ) = 3

{the queen, one ace and the nine are all spades}

● Total number of cards = 6

Probability of drawing a spade= 3/ 6

= 1/ 2

● Total number of "7" = 1

● Total number of cards = 6

Probability of drawing a 7

= 1/ 6

Now, what's asked is the difference in the probabilities of drawing a spade and a seven.

= 1/ 2 - 1/ 6

= 3/ 6 - 1/ 6

= 2/ 6

= 1/ 3

Hence, 1/ 3 of a greater chance of drawing a spade over a 7.

You might be interested in

PLEASE help due today

fomenos

Answer: Number 3; $1250

Number 4; Salesperson A ($7428.30)

Number 5; 18%

Number 6; Rent 780, Food 900, Medical 450, Clothes 300, Miscellaneous 570.

Step-by-step explanation: (No 3) The principal amount is 5000, the rate is 5% (0.05) and the time in years is 5. The formula for calculating simple interest is as follows;

I = P x R x T

I = 5000 x 0.05 x 5

I = 1250

Therefore Joanna will pay $1,250 as interest

(No 4) The amount made by both salespersons is shown as follows;

A = 11% x 67530

A = 0.11 x 67530

A = 7,428.30

B= 8% x 85740

B = 0.08 x 85740

B = 6,859.20

Therefore from the calculations above, salesperson A made more commission and the amount made is $7,428.30

(5) John's earning is 38000 and he paid 6840 for entertainment. The percentage paid for entertainment therefore is as follows;

Percent paid = (entertainment/total income) x 100

Percent paid= (6840/38000) x 100

Percent paid = 684000/38000

Percent paid = 18

Therefore he paid 18% for entertainment

(6) Nora makes a total of 3000 a month broken down as follows;

Rent = (26/100) x 3000

Rent = 0.26 x 3000

Rent = 780

Food = (30/100) x 3000

Food = 0.30 x 3000

Food = 900

Medical = (15/100) x 3000

Medical = 0.15 x 3000

Medical = 450

Clothes = (10/100) x 300

Clothes = 0.10 x 3000

Clothes = 300

Miscellaneous = (19/100) x 3000

Miscellaneous = 0.19 x 3000

Miscellaneous = 570

4 0

3 years ago

Read 2 more answers

Determine the time necessary for P dollars to double when it is invested at interest rate r compounded annually, monthly, daily,

Rudik [331]

Answer:

Part 1) 8.17 years

Part 2) 4.98 years

Part 3) 4.95 years

Part 4) 4.95 years

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part 1) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded annually

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=1$

substitute in the formula above

$2p=p(1+\frac{0.14}{1})^{t}$

$2=(1.14)^{t}$

Apply log both sides

$log(2)=log[(1.14)^{t}]$

$log(2)=(t)log(1.14)$

$t=log(2)/log(1.14)$

$t=8.17\ years$

Part 2) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded monthly

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=12$

substitute in the formula above

$2p=p(1+\frac{0.14}{12})^{12t}$

$2=(\frac{12.14}{12})^{12t}$

Apply log both sides

$log(2)=log[(\frac{12.14}{12})^{12t}]$

$log(2)=(12t)log(\frac{12.14}{12})$

$t=log(2)/12log(\frac{12.14}{12})$

$t=4.98\ years$

Part 3) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded daily

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=365$

substitute in the formula above

$2p=p(1+\frac{0.14}{365})^{365t}$

$2=(\frac{365.14}{365})^{365t}$

Apply log both sides

$log(2)=log[(\frac{365.14}{365})^{365t}]$

$log(2)=(365t)log(\frac{365.14}{365})$

$t=log(2)/365log(\frac{365.14}{365})$

$t=4.95\ years$

Part 4) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% continuously

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14$

substitute in the formula above

$2p=p(e)^{0.14t}$

Simplify

$2=(e)^{0.14t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.14t}]$

$ln(2)=(0.14t)ln(e)$

Remember that ln(e)=1

$ln(2)=(0.14t)$

$t=ln(2)/(0.14)$

$t=4.95\ years$

4 0

3 years ago

Jordan solved the equation −7x + 25 = 48; his work is shown below. Identify the error and where it was made.

fenix001 [56]

Answer:

step 3: he should have divided both sides by -7

8 0

3 years ago

2.(a+bc)+cb+ab+ac-3.(ab-cb-ba+bc)

SVETLANKA909090 [29]

2(a+bc)=2a+2bc
3.(ab-cb-ba+bc)= 3ab-3cb-3ba+3bc
Since the brackets and multiplication have a higher order than the rest.

Cb=Bc
Ab=ba
Ac=Ca

Because multiplication is commutative.

2a+2bc + cb +ab + ac -(3ab-3cb-3ba+3bc)

2a + 2bc + cb + ab + ac(+ -3ab - - 3cb - -3ba +-3bc)

2a + 2bc + cb + ab + ac -3ab + 3cb + 3ba -3bc

2a + (2bc-3bc +cb + 3cb ) + (ab -3ab + 3ba) + ac

=2a + 3cb + ba+ ac OR 2a +3bc + ab + ac

The Or is just a different way to write it.

Hope this helps

4 0

3 years ago

Triangle PIG was rotated to create triangle P'I'G'. Describe the transformation using details and degrees.

insens350 [35]

The rotation of the triangle is 270 degrees clockwise, or 90 degrees counterclockwise. Most commonly, clockwise measurements are used when it comes to rotations.

I hope this helped. Let me know if I was correct please.

6 0

3 years ago

I don't really understand the question so can someone help me answer the question please?​

I don't really understand the question so can someone help me answer the question please?