Answer:

Step-by-step explanation:
The given initial value problem is;

Let

Differentiating both sides of equation (1) with respect to
, we obtain:

Differentiating both sides of equation (2) with respect to
gives:

From equation (1),

Putting t=0 into equation (2) yields

Also putting t=0 into equation (3)

The system of first order equations is:

Answer:

General Formulas and Concepts:
<u>Algebra I</u>
<u>Calculus</u>
Antiderivatives - integrals/Integration
Integration Constant C
U-Substitution
Integration Property [Multiplied Constant]: 
Trig Integration:
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Integrate Pt. 1</u>
- [Integral] Factor fraction denominator:

- [Integral] Integration Property - Multiplied Constant:

<u>Step 3: Identify Variables</u>
<em>Set up u-substitution for the arctan trig integration.</em>

<u>Step 4: Integrate Pt. 2</u>
- [Integral] Substitute u-du:

- [Integral] Trig Integration:
![\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B9%7D%5B%5Cfrac%7B1%7D%7B%5Cfrac%7B2%7D%7B3%7D%7Darctan%28%5Cfrac%7Bu%7D%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5D%20%2B%20C)
- [Integral] Simplify:
![\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B9%7D%5B%5Cfrac%7B3%7D%7B2%7Darctan%28%5Cfrac%7B3u%7D%7B2%7D%29%5D%20%2B%20C)
- [integral] Multiply:

- [Integral] Back-Substitute:

Topic: AP Calculus AB
Unit: Integrals - Arctrig
Book: College Calculus 10e
Answer: what’s your question?
Step-by-step explanation:
9514 1404 393
Answer:
-130 °C
Step-by-step explanation:
The change is found by subtracting the start temperature from the finish temperature. It is ....
-60 °C - 70 °C = -130 °C
Answer:
82
Step-by-step explanation:
50+32 =82 and this has to be longer so this is me making it longer