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Alenkinab [10]
4 years ago
9

A student scored a 72, 75, and 83 on the first three tests. All tests have a possibility of 100 points (no bonus points). Is it

possible for the student to raise their overall average to an 80 on test
Mathematics
1 answer:
alexira [117]4 years ago
7 0
Add 72, 75, and 83, which equal 230. Then, since there are three values, you divide the total (230) by 3, which would equal 76.6 (cont), therefore meaning they can only raise their average (using the three tests, from a base grade of 0) to a 76.6 percent (or 77 if teacher rounds grade)
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Adding &subtracting x-60=20
Alex777 [14]
Just add to find X
20 + 60 = 80
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X = 80
To make sure plug it in
80 - 60 = 20
The equation is true
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x = 80 is your answer
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3 years ago
Find the volume of a cone with a base radius of 4 ft and a height of 6 ft. I really need help with this asap. I will give 10 poi
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Step-by-step explanation:

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bija089 [108]

Let <em>n</em> be the unknown number. We can write it as

<em>n</em> = 10<em>a</em> + <em>b</em>

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Reversing the digits gives another number

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The first number is increased by 54 when the digits are reversed, which means

<em>m</em> = <em>n</em> + 54   →   10<em>b</em> + <em>a</em> = 10<em>a</em> + <em>b</em> + 54   →   9<em>b</em> - 9<em>a</em> = 54   →   <em>b</em> - <em>a</em> = 6

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<em>a</em> = 3<em>b</em>

Substitute this into the previous equation and solve for <em>b</em> :

<em>b</em> - <em>a</em> = <em>b</em> - 3<em>b</em> = -2<em>b</em> = 6   →   <em>b</em> = -3

Solve for <em>a</em> :

<em>a</em> = 3<em>b</em> = 3(-3) = -9

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3 0
3 years ago
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Consider the following equation.
Natali [406]

\\ \tt\longmapsto 6(-x)+4=3x+1

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\\ \tt\longmapsto -6x-3x=1-4

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