It looks like you're asked to find the value of y(-1) given its implicit derivative,

and with initial condition y(2) = -1.
The differential equation is separable:

Integrate both sides:


Solve for y :



![y = -\dfrac1{\sqrt[3]{3x+C}}](https://tex.z-dn.net/?f=y%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x%2BC%7D%7D)
Use the initial condition to solve for C :
![y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5](https://tex.z-dn.net/?f=y%282%29%20%3D%20-1%20%5Cimplies%20-1%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes2%2BC%7D%7D%20%5Cimplies%20C%20%3D%20-5)
Then the particular solution to the differential equation is
![y(x) = -\dfrac1{\sqrt[3]{3x-5}}](https://tex.z-dn.net/?f=y%28x%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x-5%7D%7D)
and so
![y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}](https://tex.z-dn.net/?f=y%28-1%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes%28-1%29-5%7D%7D%20%3D%20%5Cboxed%7B%5Cdfrac12%7D)
Answer:
(3, 4 )
Step-by-step explanation:
5x + 3y = 27 → (1)
2x + y = 10 ( subtract 2x from both sides )
y = 10 - 2x → (2)
substitute y = 10 - 2x into (1)
5x + 3(10 - 2x) = 27
5x + 30 - 6x = 27
- x + 30 = 27 ( subtract 30 from both sides )
- x = - 3 ( multiply both sides by - 1 )
x = 3
substitute x = 3 into (2)
y = 10 - 2(3) = 10 - 6 = 4
solution is (3, 4 )
Answer:
-8n + 9
Step-by-step explanation:
Given that,
A = -3n + 2
B = 5n - 7
Before solving you have to know that,
( + ) × ( + ) = ( + )
( - ) × ( - ) = ( + )
( + ) × ( - ) = ( - )
Let us solve now.
A - B
-3n + 2 -(5n - 7)
-3n + 2 - 5n + 7
Combine like terms
-3n - 5n + 2 + 7
-8n + 9
Hope this helps you.
Let me know if you have any other questions :-)