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ki77a [65]
2 years ago
13

Circle all the words that describe the quadrilateral

Mathematics
2 answers:
Fudgin [204]2 years ago
5 0
A quadrilateral is a shape with 4 sides. For number 2 you would circle square and rectangle. For number 3 you would circle trapezoid.
svp [43]2 years ago
3 0
Rombus I guess I don’t really know
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9=+4xbnmn74564 sssss
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Katie has to drive 15 miles east and 36 miles north to get to her aunt's house. Which of the following equations could be used t
Leya [2.2K]

Answer:  a2 + 152 = 362

Step-by-step explanation:

7 0
3 years ago
How can x-(2/3)+(5/6) be solved for x in one step? Add (2/3) to both sides. Add (5/6) to both sides. Subtract (2/3) from both si
shutvik [7]

Subtract 2/3 from both sides.

8 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Quadratic Equations<br> How do I solve a quadratic equation?
malfutka [58]
There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
 ex:        x^2+ 4x + 3 =0
             (x+3) (x+1) = 0
              x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)

2) The other way to solve a quadratic function is by using a formula:
    given: ax^2 +bx +c=0
    x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
    
 ex: 3x^2 + 4x -2=0
    x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
                                                        and
                                              x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
5 0
3 years ago
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