Answer:
0.3667 or 36.67%
Step-by-step explanation:
The probability of getting at least 1 defective hard disk among the 5 (P(X>0)) is equal to 100% minus the probability of getting none defectives (1-P(X=0)).
If 23 out of 25 hard disks are non-defective, the probability is:

The probability that there is at least 1 defective hard disk is 0.3667 or 36.67%.
Answer:
i believe the answer will be 23
<span>the product of one term of a multiplicand and one term of its multiplier.</span>
Answer:
0.66
Step-by-step explanation:
33 * 0.02 = 0.66