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mr Goodwill [35]
3 years ago
14

At a popular arcade, Lana bought a game card worth 135 game credits. Lana and a friend used the card to play Flappy Fish, a game

that costs 4 credits per game. They each played the game 7 times. Which equations could represent n, the number of credits remaining on the card? Select all that apply.
Mathematics
2 answers:
Leto [7]3 years ago
6 0
N=135-4(14). The number of coins remaining would be the initial amount (135) minus the amount used on the game. You could simply find the product of 4 and 14 since the game costs 4 coins per game and they each played 7 times. After that step is done...the equation could be further broken down to N=135-56. Getting the answer of N= 79 coins remaining. Another equation could be N=135-4x. The x in this case would represent how many times the game was played. Then, you could put the 14 in because they each played 7 times. I hope this helps. Next time, include the answer that were given. I was unsure about the “select all that apply” as the there were no choices given.
Ghella [55]3 years ago
3 0

Answer:

rbrbrwr

Step-by-step explanation:

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If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num
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Step-by-step explanation:

Solution,

Let the fraction be'\frac{x}{y}'.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

\frac{x+2}{y+2}=\frac{1}{2}

On using cross multiplication method, we get;

2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

\frac{x-2}{y-2}=\frac{1}{3}

On using cross multiplication method, we get;

3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2

Now Substituting the equation 1 in equation 1 we get;

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Now Substituting the value of x in equation 1 we get;

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Hence The original fraction is \frac{6}{14}.

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5 0
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5 0
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