Question

Segment KL is a diameter of circle Q. Circle Q is represented by the equation (x − 11)2 + (y + 15)2 = 7. What is KL?

Answer 1

Answer:

$(C)2\sqrt{7}$

Step-by-step explanation:

Given a circle Q represented by the equation:

$(x -11)^2 + (y + 15)^2 = 7.$

Comparing with the standard form of the equation of a circle center (h,k) of radius r:

$(x-h)^2+(y-k)^2=r^2$

We have:

$r^2=7$

We take the square root to obtain the radius, r of the circle.

$r=\sqrt{7}$

Since segment KL is a diameter of circle Q; and

Diameter =Radius X 2

Therefore:

$|KL|=2\sqrt{7}$

Answer 2

Answer:

C

Step-by-step explanation: