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2 years ago

13

Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?

1 answer:

melisa1 [442]2 years ago

6 0

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 $m^2$ .

Because there are 100 centimeters in a meter and you are asking for area, you must multiply by $100^2$ to get 4000000 $cm^2$ .

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<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^

marta [7]

Answer:

$-\frac{5}{4x}$

Step-by-step explanation:

<h2> $\left(-5x^3\right)^3\div \left(10x^5\right)^2$ </h2><h2> $\frac{-5^3x^9}{\left(10x^5\right)^2}$ </h2><h2> $\frac{-5^3x^9}{10^2x^{10}}$ </h2><h2> $\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}$ </h2><h2> $\frac{-5x^9}{2^2x^{10}}$ </h2><h2> $\frac{-5}{2^2x}$ </h2>

$-\frac{5}{4x}$

- hope it helps! -

<h2 />

3 0

1 year ago

I need help with this question

4vir4ik [10]

Answer:

y = 3

Step-by-step explanation:

y/9 = 2/6

y/9 = 1/3 (dividing by 2in both numerator and denominator.)

CROSS MULTIPLYING WE GET

3y = 9*1

3y = 9

y = 3

4 0

2 years ago

The circumference of a circle is 53.3853.38 centimeters.

zepelin [54]

Answer:

dcfvghbjk

Step-by-step explanation:

4 0

2 years ago

AlekseyPX

Answer:

D.

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = $\frac{m(b) - m(a)}{b - a}$

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = $\frac{4 - (-12)}{2 - (-2)}$

= $\frac{16}{4}$

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = $\frac{n(b) - n(a)}{b - a}$

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = $\frac{6 - (-6)}{2 - (-2)}$

= $\frac{12}{4}$

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = $\frac{q(b) - q(a)}{b - a}$

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = $\frac{-12 - (-4)}{2 - (-2)}$

= $\frac{-8}{4}$

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = $\frac{p(b) - p(a)}{b - a}$

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = $\frac{-4 - 12}{2 - (-2)}$

= $\frac{-16}{4}$

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

3 0

2 years ago

Find "both answers.

amid [387]

Sorry yo i just need points :/

5 0

2 years ago