Answer:
FV= $6,616.38
Explanation:
Giving the following information:
Annual cash flow= $500
Number of periods (n)= 8
Interest rate= 14%
<u>To calculate the future value, we need to use the following formula:</u>
FV= {A*[(1+i)^n-1]}/i
A= annual cash flow
FV= {500*[(1.14^8) - 1]} / 0.14
FV= $6,616.38
Complete Question: Many banks and phone companies now charge fees for once-free services to ensure minimum customer revenue levels. This helps the banks to ________.
A) reduce the rate of customer defection
B) make low-profit customers more profitable
C) enhance the growth potential for each customer through cross-selling
D) increase the longevity of the customer relationship
E) focus disproportionate effort on high-value customers
Answer:
B) make low-profit customers more profitable
Explanation:
Many banks and phone companies now charge fees for once-free services to ensure minimum customer revenue levels. This helps the banks to make low profit customers more profitable.
The basic logic behind this strategy is that when customers find something coming free, then they start taking it for granted, they don't pay much attention to it, therefore, when the some services are free, customers will not be spending much on them, like upgrading, monthly plan up-gradations, monthly or annual subscriptions. Consequently, to turn the those customers into highly valuable customers, companies charge for the services which were free of cost in the past.
Answer:
The expected return = 10.739.
Explanation:
Given risk-free rate of return = 2.3 per cent
Market expected return = 12 percent
The value of beta = 0.87
Use the below formula to find the expected return.
The expected return = Risk free rate of return + Beta × (Market expected return - risk free rate of return)
The expected return = 2.3 + 0.87 (12 – 2.3)
The expected return = 10.739
The dimensions of the cylinder can be used to minimise cost of manufacture.
<h3>How to we find minimised cost?</h3>
Let's ignore the metal's thickness and assume that the material cost to manufacture is precisely proportionate to the surface area of a perfect cylinder.
A=2πr(r+h)
Given that V=1000=r2h and h=1000=r2, we can write
A=2πr(r+1000πr2)
A=2πr2+2000r−1
By setting the derivative to zero, we may determine the value of r that minimises A:
A′=4πr−2000r−2
0=4πr−2000r−2
2000r−2=4πr
2000=4πr3
r=500π−−−√3
r=5.419 + cm
h=1000πr2=10.838 + cm
The can with the smallest surface area has a volume of 1000 cm 3 and measures 5.419+ cm in radius and 10.838+ cm in height. The can has a surface area of 553.58 cm 2. Given a constant volume, the cylinder with diameter equal to height has the least surface area.
Can surface area (cm2) versus. radius (cm), where capacity = 1000cm 3.
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