Answer:
Domain: (-∞, ∞) or All Real Numbers
Range: (0, ∞)
Asymptote: y = 0
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Step-by-step explanation:
The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.
The range is from 0 to ∞. This where all values of y are defined.
An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.
The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Answer:
He has to divide 12/3 first
Step-by-step explanation:
it’s like pemdas you have to do that first then you go on to added the 3+ whatever 12/3 is
= <span><span>−x</span>+6</span>
<span>=<span><span> −<span>3x</span></span>+3</span></span>
<span>= </span><span><span>−x</span>+6</span>
= <span><span>2x</span>−3</span>
<span>= <span><span>−<span>4x</span></span>−<span>17</span></span></span>
<span>WKLX
W(2, −3),
K(4, −3),
L(5, −2) ,
X(1, −2)
TRANSLATED 4 UNITS RIGHT and 3 UNITS DOWN to produce W'K'L'X
4 units right means the x coordinate is affected. Since the moving to the right, we add 4 to the x values of each vertice.
W = 2 + 4 = 6
K = 4 + 4 = 8
L = 5 + 4 = 9
X = 1 + 4 = 5
3 units down means the y axis is affected. We add 3 to the value of y but keep the negative sign.
W = -3 + -3 = -6
K = -3 + -3 = -6
L = -2 + -3 = -5
X = -2 + -3 = -5
The correct answer is: </span><span>W′(6, −6), K′(8, −6), L′(9, −5) , and X′(5, −5)</span>
P=25r-12500
p=125000 and r=?
125000=25r-12500
+12500 +12500
25r= 137500
r=137500/25
r= 5,500
Therefore the answer is B) 5,500
