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natulia [17]
3 years ago
9

The following stem-and-leaf plot shows the on-record attendance for regional charity drive meetings.

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0
I’ll answer when I get home
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Milo has 2 hours of free time. He spends 2/4 of an hour with his dog he spends 3/4 of an drawing. What fraction of an hour dose
TEA [102]

Answer:

3/4 time left

Step-by-step explanation:

7 0
3 years ago
I need an answer...............................
navik [9.2K]

Answer:

8 i think

Step-by-step explanation:

4 0
3 years ago
The cost, C, in millions of dollars of producing T million tons of steel is modeled by the equation C = 220T + 1890.
kobusy [5.1K]

C = 220T + 1890.

Solve the equation for T.

220T = C - 1890

T = C/220 - 8.6

The steel produced is expected to be sold at a price of $310 per ton.

310 $/ton is a rate or slope. Write a linear equation where x is tons of steel produced and y is selling price of the steel.

y = 310x

Write and solve an equation to find the amount of steel produced if the selling price is equal to the cost of production.

* Here, note that the cost of production and tons of steel in the first equation is in the millions.  The equation we just wrote for the selling price was in x tons of steel. This only matters in regards to the units you specify because; million/million = 1

The unit multiplier of all variables must be specified as same. Either everything is in millions or not.

Here, I'll leave everything in millions, change x (tons of steel) to T (mill tons steel) and "y" to "S" in million dollars selling price.

S = 310T

Set equal to Cost equation.

220T + 1980 = 310T

Solve for T, million tons of steel produced.

1980 = 310T - 220T

1980 = 90T

T = 1980/90

T = 22 million tons steel produced


7 0
3 years ago
In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is
Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of  adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

\mu=np=300\times0.077=23.1

\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62

Now, using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponding to 26 will be :-

z=\dfrac{26-23.1}{4.62}\approx0.63

Using standard distribution table for z , we have

P-value=P(z\geq0.63)=1-P(z

=1-0.7356527=0.2643473\approx0.2643

Hence, the probability that at least 26 in the sample are unemployed  =0.2643

6 0
3 years ago
Directions: Evaluate the following combinations and determine the value of the
Andru [333]

Answer:

1. C(9,4) : n=9, s=4

2. C(10,5) : r=5

3. C(5,5) : n=5

4. C(7,7) : n=6

5. C(18,17) : r=3

Step-by-step explanation:

4 0
3 years ago
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