You put the 0 if it is close to 0, the 1/2 if it is closer to half, 1 if it is equal or closer to one, and the >1 if it is over one
Answer:4x2−6x−4
Step-by-step explanation:
(4x+2)(x−2)
=(4x+2)(x+−2)
=(4x)(x)+(4x)(−2)+(2)(x)+(2)(−2)
=4x2−8x+2x−4
=4x2−6x−4
Answer:
I would just guess, but if i were to actually think about it, i would think C. I hope it helps, and blame it on me if you fail.
Step-by-step explanation:
Answer:
(a) 0.107 million per year
(b) 0.114 million per year
Step-by-step explanation:

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000,
and in 2014,
. Mathematically,


(b) The instantaneous rate of change is determined by finding the differential derivative at that year.
The result of differentiating functions of the firm
(where
is a constant) is
. Let's use in this in finding the derivative of
.

In the year 2014,
.

Formula for perimeter of a rectangle: P = 2W + 2L
Here, P = 2(x-3 ) cm + 2(3x+7) cm = 2x - 6 + 6x + 14 (cm)
Combine like terms: 8x + 8 cm (simplest form) This is the perimeter.
Now let x = 4: P(x=4) = 8(4) + 8 cm = 40 cm