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3 years ago

Hausbbshakbsusjanaozubss

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

that is a very good question

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How many solutions does the equation 5x + 1 = −5x + 10 have?

storchak [24]

Answer:

9/10 (one solution)

Step-by-step explanation:

6 0

4 years ago

The owner of the Outdoor Furniture Center decides to use the 120% markup. At the end on

lana66690 [7]

Answer: The total price of a bench is 1.008x.

Step-by-step explanation:

Since we have given that

Let the cost price be 'x'.

Mark up % = 120%

So, Mark up value would be

$\dfrac{120}{100}x\\\\=1.20x$

Discount % = 20%

Amount of discount is given by

$\dfrac{20}{100}\times 1.2x\\\\=0.2\times 1.2x\\\\=0.24x$

So, it becomes,

Amount after discount is given by

$1.2x-0.24x\\\\=0.96x$

Sales tax = 5%

Amount of sales tax would be

$\dfrac{100+5}{100}\times 0.96x\\\\=\dfrac{105}{100}\times 0.96x\\\\=1.05\times 0.96x\\\\=1.008x$

Hence, the total price of a bench is 1.008x.

6 0

4 years ago

1 and 2 please answer for me :)

bezimeni [28]

Number 1 is proportional because if u simplify 2/24 u get 1/12
number 2 is the book palace because it goes right through the orgin , it is proportional

7 0

3 years ago

Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do

Liula [17]

Answer:

The population of bacteria can be expressed as a function of number of days.

Population = $5*2^{n-1}$ where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day= $5 * 2^{0} = 5$

Number of bacteria on the second day = $5 * 2^{1} = 10$

Number of bacteria on the third day = $5*2^{2} = 20$

Number of bacteria on the fourth day = $5*2^{3} = 40$

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as $5*2^{n-1}$ where n is the number of days since the beginning.

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3 years ago

40.6 in numerical form

oksano4ka [1.4K]

What's your question so I could help?

6 0

3 years ago