Problem 1
Draw a straight line and plot X anywhere on it.
Use your compass to trace out a circle with radius 1.5 cm. The circle intersects the line at two points. Let's make Y one of those points.
Also from point X, draw a circle of radius 2.5
This second circle will intersect another circle of radius 3.5 and this third circle is centered at point Z.
Check out the diagram below to see what I mean.
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Problem 2
Draw a straight line and plot L anywhere on it.
Adjust your compass to 4 cm in width. Draw a circle around point L.
This circle crosses the line at two spots. Focus on one of those spots and call it M.
Draw another circle centered at point M. Keep the radius at 4 cm.
The two circles intersect at two points. Focus on one of the points and call it N.
The last step is to connect L, M and N to form the equilateral triangle.
See the image below.
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Problem 3
I'm not sure how to do this using a compass and straightedge. I used GeoGebra to make the figure below instead. It's a free graphing and geometry program which is very useful. I used the same app to make the drawings for problem 1 and problem 2 earlier.
Answer:
the probability that no customer will arrive in the next 6 minutes = 0.36788 = 0.368
Step-by-step explanation:
If there are 10 customers per hour, this translates to 1 customer per 6 minutes
So, if there's a mean of 1 customer per 6 minutes, to obtain the probability that no customer will come in a 6 minute interval, this becomes a Poisson distribution problem.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 1 customer per 6 minutes
x = 0 customer per 6 minutes
P(X=0) = (e⁻¹)(1⁰)/0! = 0.36788 = 0.368
The answer is 1 0 2 3 8
Glad to help :D
Answer:
The union of two event
Step-by-step explanation:
Addition law of probability define that probability of two event is total sum of probability of any event subtract the probability of both events
There are two rules in addition law:
Addition law 1 - when both event are mutually exclusive, then probability of either event is the sum of each event probability.
P( A or B) = P(A) +P(B)
Addition law 2 - when both events are non mutually exclusive then there in addition to the individual probability there is some overlap .
P( A or B) = P(A) +P(B) - P(A and B)
Answer:
2. angle bisector splits into even halves
Step-by-step explanation:
that's all i can assist with sorry, proofs still confuse me!
