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Ket [755]
3 years ago
12

A truth table with three inputs has how many switch combinations?

Computers and Technology
1 answer:
Pie3 years ago
7 0
Three inputs have 8 possible states.
Here they are:

0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1

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The 'client area' of a window is the area used to display the contents of the window (thus a title bar or border would lie outsi
Lady_Fox [76]

Answer:

<u>Window.java</u>

  1. public class Window {
  2.    int width;
  3.    int height;
  4.    public Window(int width, int height){
  5.        this.width = width;
  6.        this.height = height;
  7.    }
  8.    public int getWidth(){
  9.        return width;
  10.    }
  11.    public int getHeight(){
  12.        return height;
  13.    }
  14.    public int getClientAreaHeight(){
  15.        return getHeight();
  16.    }
  17. }

<u>Main.java</u>

  1. public class Main {
  2.    public static void main (String [] args) {
  3.        Window win1 = new Window(12, 15);
  4.        System.out.println(win1.getClientAreaHeight());
  5.    }
  6. }

Explanation:

<u>Window.java</u>

There is a Window class with two int type attributes, width and height (Line 1 - 3).

The constructor of this class will take two inputs, width and height and set these input to its attributes (Line 5 - 8). There are two methods getWidth and getHeight which will return the value of attributes width and height, respectively (Line 10 - 16).

The required new method getClientAreaHeight is defined in line 18 -20. This method will call the getHeight method to return the height value of the window (Line 19).

<u>Main.java</u>

We test the Window class by creating one Window instance and call the getClientAreaHeight method and print the return output (Line 1 -6).

We shall see 15 is printed.

4 0
3 years ago
Focusing on the general characteristics of a problem or object, while ignoring the details, is a technique called
Taya2010 [7]

Answer:

Abstraction

Explanation:

In computer science, abstraction has a similar definition. It is a simplified version of something technical, such as a function or an object in a program. The goal of "abstracting" data is to reduce complexity by removing unnecessary information. At some level, we all think of computers in abstract terms.

5 0
2 years ago
What type of software repairs or improves a larger application that is already installed on a system?
earnstyle [38]

Answer:

<h2>Mapping</h2>

Explanation:

<h2>Hope it helps you</h2>
7 0
2 years ago
Read 2 more answers
The following problem illustrates the way memory aliasing can cause unexpected program behavior. Consider the following function
laila [671]

Answer:

A

Explanation:

The value will be the original stored in the int variables. This is because the method swap(int xp, int yp) accepts xp and yp parameters by value (They are passed by value and not by reference). Consider the implementation below:

public class Agbas {

   public static void main(String[] args) {

   int xp = 2;

   int yp = xp;

   swap(xp,yp); //will swap and print the same values

       System.out.println(xp+", "+yp); // prints the original in values 2,2

 int xp = 2;

   int yp = 5;

   swap(xp,yp); // will swap and print 5,2

       System.out.println(xp+", "+yp); // prints the original in values 2,5

   }

   public static void swap(int xp, int yp){

       int temp = xp;

       xp = yp;

       yp = temp;

       System.out.println(xp+", "+yp);

   }

}

5 0
3 years ago
What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r;
ycow [4]

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

The function is defined as: myMathFunction(int a, int r, int counter)

It initially gets the following as its input from the main method

a= 1; r = 2; counter = 0

Its operation goes thus:

val = a*r; 1 * 2 = 2

Print val; Prints 2

if (counter > 4) { System.out.print("End"); } : Not true

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 2; r = 2; counter = 1

val = a*r; 2 * 2 = 4

Print val; Prints 4

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 4; r = 2; counter = 2

val = a*r; 4 * 2 = 8

Print val; Prints 8

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

val = a*r; 8 * 2 = 16

Print val; Prints 16

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 16; r = 2; counter = 4

val = a*r; 16 * 2 = 32

Print val; Prints 32

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 32; r = 2; counter = 5

val = a*r; 32 * 2 = 64

Print val; Prints 64

if (counter > 4) { System.out.print("End"); } : True

<em>This prints "End"</em>

So; the output of the program is:

2 4 8 16 32 64 End

3 0
3 years ago
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