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shusha [124]
3 years ago
8

The perimeter of the original rectangle is 16 feet. A small rectangle has a length of 6.2 feet and width of 1.8 feet. A larger r

ectangle has a length of 12.4 feet and width of blank. Not drawn to scale What is the perimeter of the enlarged rectangle? Round to the nearest tenth if necessary.
Mathematics
2 answers:
Flauer [41]3 years ago
7 0

Answer:

32 ft

Step-by-step explanation:

2·1.8 ft = 3.6 ft.

GalinKa [24]3 years ago
5 0

Answer:

  32 ft

Step-by-step explanation:

The length of the larger rectangle is double that of the smaller one. If we assume the rectangles are similar, the perimeter will be double as well:

  2·(16 ft) = 32 feet . . . . perimeter of larger rectangle

__

The width of the larger one is 2·1.8 ft = 3.6 ft.

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Just want to double check our answer.
bearhunter [10]

0 divided by 2 is 0.

You can use the multiplicative identity property: the product of any number and zero is still zero.

Hope this helped :)

3 0
3 years ago
Help urgent, which functions are bounded below but not above? Choose all answers that apply.
evablogger [386]

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

c. is bounded below at y = 0 and unbounded above

d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

h. is unbounded both above and below

i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

3 0
2 years ago
The function h(t) = -16t2 + 48t + 28 models the height (in feet) of a ball where t is the time (in seconds).
Alex17521 [72]

Answer:

64

Step-by-step explanation:

<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have h'(t) = -32t + 48, which equals zero when t = 3/2 = 1.5. The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.

<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.

5 0
2 years ago
Samantha wants to use her savings of 1150 to buy shirts and watches for her family. The total price of the shirt she bought was
ioda

<u>Answer-</u>

<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>

<u>Solution-</u>

The amount of money Samantha has in her savings account = $1150

She wants to buy shirts and watches.

Cost of one shirt = $84

Cost of each watch = $99

Let she can buy maximum of x watches, so the net price of the watches is $99x.

Then,

\Rightarrow 99x+84=1150\\\\\Rightarrow 99x=1150-84\\\\\Rightarrow 99x=1066\\\\\Rightarrow x=\dfrac{1066}{99}\\\\\Rightarrow x=10.77

As the number of watches can not be in fraction, so at most she can buy 10 watches.

8 0
3 years ago
What is the measure of o
Helga [31]

Answer:

D

Step-by-step explanation:

We need the formula for arc length (in radians) to solve this problem. The formula is:

s=r \theta

Where

s is the arc length

r is the radius of the circle

\theta is the intercepted angle

In this diagram, we can see that  \theta  is beign intercepted by the big arc with measure 20 cm. So arc length, s, is 20

Also, if we look, we see that the radius is 5 cm, so r = 5

Now, we substitute into formula and find \theta:

s=r\theta\\20=5\theta\\\theta=\frac{20}{5}\\\theta=4

This is given in radians, so \theta is 4 radians

D is the correct answer choice.

6 0
2 years ago
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