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3 years ago

Alex can plant

Mathematics

1 answer:

Ganezh [65]3 years ago

4 0

Answer:

yeah! cool so you add then divied and boom yw

Step-by-step explanation:

add and divide like I said! hope this helPwdd

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Rounding number to the nearest hundredth

bearhunter [10]

Answer:

the answer is 11.66

Step-by-step explanation:

because 3 cant give 0 anything 9 will make 1, 2 but 2 cant change 6

6 0

2 years ago

Read 2 more answers

Which graph shows y = 2x – 12?

kozerog [31]

Answer:

(0,6) (0,-12)

Step-by-step explanation:

6 0

3 years ago

Can u show the step and thanks

Rudiy27

Answer:

B) 378 students could be expected to attend the game.

Step-by-step explanation:

Out of 40 students, 45% agreed,

45% of 40

= 45/100 * 40

= 18 students,

18 students out of 40 agreed.

So, Out of 840 students 18/40 * 840 students would be expected to agree. We get :- 378

4 0

3 years ago

225 is 75% of what number?

Licemer1 [7]

300? i think its right but im not sure

7 0

3 years ago

A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b

nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$p = 0.1$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}$

$0.04\sqrt{n} = 0.588$

$\sqrt{n} = \frac{0.588}{0.04}$

$\sqrt{n} = 14.7$

$(\sqrt{n})^{2} = (14.7)^{2}$

$n = 216$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0

4 years ago