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Arte-miy333 [17]
2 years ago
6

Alex can plant

Mathematics
1 answer:
Ganezh [65]2 years ago
4 0

Answer:

yeah! cool so you add then divied and boom yw

Step-by-step explanation:

add and divide like I said! hope this helPwdd

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Find the value of the variable and BC, if B is between A and C.<br> AB = 5x, BC = 3x-1, AC = 47
schepotkina [342]

Answer:

17

Step-by-step explanation:

AC = AB + BC

Since we know what each variable equals, we can write out the equation as shown:

47 = 5x + 3x - 1

Combining like terms:

47 = 8x - 1

Add 1 on both sides:

48 = 8x

Divide 8 on both sides:

X = 6

Now that we know what X equals, we can solve BC.

BC = 3(6) - 1

BC = 18 - 1

BC = 17

Therefore BC = 17.

4 0
2 years ago
Which inequality is true?
ICE Princess25 [194]
I believe the second one
4 0
3 years ago
Read 2 more answers
A lawn-mowing company is trying to grow its business. It had 26 clients when they started its business and wants to increase by
Likurg_2 [28]

Answer:

B. f(x) = 3x + 26;26≤ y ≤ 35

Step-by-step explanation:

This would be a linear equation in the form

y= mx+b

where b is the initial value (or 26 clients)

m is the slope, or the amount they want to increase by each week

y = 3x+26

Let x =0

y = 26 or what we start with

Let x =3, or be week 4 (we started with x= 0)

y = 3*3 +26

y =9+26

y= 35

3 0
2 years ago
Read 2 more answers
1.Ordenar de menor a mayor los siguientes números
Nataliya [291]
1. -16, -9, -3, 0, 5, 8, 25

2. 26, 13, 7, 6, 2, -1, -3, -50

Espero que esto ayude!

8 0
2 years ago
Read 2 more answers
1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a
Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

f(x)=x^2

g(x)=|x|

It is given that,

(f\circ g)(x)=|x|^2=x^2

(g\circ f)(x)=|x^2|=x^2

According to chin rule,

(f\circ g)(c)=f(g(c))=f'(g(c)g'(c)

It means, (f\circ g)(c) is differentiable if f(g(c)) and g(c) is differentiable at x=c.

Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule

3 0
2 years ago
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