eric studied for 17.5 hours for a period of 4.5 days. On the average, how much did he study each day?

What is 16500 rounded to the nearest ten thousand?

frosja888 [35]

16500 Rounded to the nearest ten thousand is 20,000

4 0

3 years ago

I need help finding the area

AleksAgata [21]

It's 192, I'm pretty sure. I hope that you get this right! :^)

7 0

2 years ago

(1/2)^2 - 6 (2 - 2/3)<br><br> Note: 1/2 and 2/3 is a fraction

shusha [124]

$\bf \left( \cfrac{1}{2} \right)^2-6\left(2-\cfrac{2}{3} \right)\impliedby recall~~\mathbb{PEMDAS}
\\\\\\
\cfrac{1^2}{2^2}-6\left( \cfrac{6-2}{3} \right)\implies \cfrac{1}{4}-6\left( \cfrac{4}{3}\right)\implies \cfrac{1}{4}-\cfrac{6\cdot 4}{3}\implies \cfrac{1}{4}-\cfrac{24}{3}
\\\\\\
\cfrac{1}{4}-8\impliedby LCD~~4\implies \cfrac{1-32}{4}\implies \cfrac{-31}{4}\implies -7\frac{3}{4}$

5 0

2 years ago

Which simplified fraction is equal to 0.53 (3 repeated)?

Morgarella [4.7K]

Hello there!

Okay, I don't know if this is a "select all that apply", but I believe that answers 1, 2, and 3 are all equivalent to 0.53.

To see how these fractions are equal, I divided the numerators by the denominators. For instance, you could have 4 over 5 (4/5) and divide 4 by 5 (4/5) to get 0.8. Now you'll do the same thing for the fractions given

24/45=0.533...
8/15=0.533...
48/90=0.533...
5/9=0.5556

As you can see, the only fraction that doesn't equal 0.53, or the outlier, is 5/9 or 0.5556

I hope this helps you out!

8 0

3 years ago

Read 2 more answers

(12x + y + z = 26

mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

$\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}26\\17\\23\end{array}\right]$ .

Step 3:

The linear system B is represented as

$\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}23\\17\\26\end{array}\right]$ .

Step 4:

The linear system C is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}4\\11\\12\end{array}\right]$ .

Step 5:

The linear system D is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}12\\11\\4\end{array}\right]$ .

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0

2 years ago