Answer:
836
Step-by-step explanation:
4 times 19 times 11
-2
We know that a positive and a negative will end in a negative result. (+) (-) = (-)

is a right triangle with base length 1 and height 8, so the area of

is

.
The average value of
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over

is given by the ratio

The denominator is just the area of
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, which we already know. The average value is then simplified to
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In the

-plane, we can describe the region

as all points

that lie between the lines

and

(the lines which coincide with the triangle's base and hypotenuse, respectively), taking

. So, the integral is given by, and evaluates to,



The correct answer is Choice A I hope it helps :)