Question

A set of sweater prices are normally distributed with a mean of 585858 dollars and a standard deviation of 555 dollars.What proportion of sweater prices are between 48.5048.5048, point, 50 dollars and 606060 dollars?

Answer 1

Answer:

Explanation:

 Mean μ = 58

standard deviation σ = 5

x₁ = 48.5 , x₂ = 60

value of t = (x₂ -  μ )/ σ

= (60 - 58) / 5 = .4

Area under normal curve = .1554

value of t = (μ -x₁)/ σ

=(58 - 48.5 )/5

= 1.9

Area under normal curve = .4713

Total area = .4713 + .1554

= .6267

= 62.67%