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3 years ago

How many days in the month of february??

1 answer:

7 0

Well it depends if it's a leap year. If it isn't a leap year there are 28 days and if we are in a leap year than there are 29 days in February. Hope that helped :)

You might be interested in

Jeffery is playing a game with two spinners below:

Mrrafil [7]

The <em>correct answer</em> is:

{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .

Explanation:

The sample space for rolling these two spinners is:

(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)

This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12

As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

3 0

3 years ago

Read 2 more answers

5•m=35 what’s the value of m

nikitadnepr [17]

Answer:

Step-by-step explanation:

5x5=35

3 0

2 years ago

You pull out the plug from the bathtub. After 30 seconds, there are 13 gallons of water left in the tub. One minute after you pu

kari74 [83]

There were 15 gallons of water to begin with. hope this helps

6 0

2 years ago

According to the scores on the last math test, 80%, or 20, of the students in the class received an A. Find the number of studen

Sladkaya [172]

80% is the same as 4/5, so 4/5 of the class= 20. That means that if there was a picture, 4 parts would be shaded, and 1 would not. 1/4 of 20 is 5, so 1 part= 5 people. 5 x 5 = 25. 25 is the answer. :)

8 0

2 years ago

Read 2 more answers

A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,

tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0

3 years ago