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Alona [7]
1 year ago
5

Exercise

Mathematics
1 answer:
svp [43]1 year ago
4 0

By addition of all the exercise and substracting it from 1 hourJavier runs on treadmill on Monday is 0.40 hour.

Now According to the question javier completed 3 repetitions of each exercise so by multiplication time taken by javier to complete each exercise is as follow;

Squats = 0.8*3= 0.24 hour

Crunches = 0.03*3 = 0.09 hour

Lunges = 0.04*3 = 0.12 hour

curls = 0.05*3 = 0.15 hour

we can calculate total time taken to complete all exercise by Addition is,

0.24 + 0.09 + 0.12 + 0.15

0.60 hour

time taken on treadmill by javier;

1 hour - 0.60 hour

0.40 hour

Read more about Addition here:

brainly.com/question/20658817

#SPJ4

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Need help with these 2 questions ASAP, no links and a answer with an explanation will get brainly
marin [14]

Answer:

Yes, Fiona is correct

Step-by-step explanation:

WHen the pythagorean theorem is applied to the side lengths (2^2 + 4^2 = c^2), the result for c^2 is 20. The correct answer would be sqrt.20. But Fiona is also correct becuase sqrt of 20 can be simplified to sqrt.4 * sqrt.5; which equals 2*sqrt.5

3 0
3 years ago
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Answer:

The equation to represent the rate of receding water level is                     L = 34 (0.5)^{d}   .

Step-by-step explanation:

Given as :

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The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

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The level of water after d days = initial level of water × ( (1-\dfrac{\textrm Rate}{100})^{Time}

I.e L = 34 × ( (1-\dfrac{\textrm 50}{100})^{d}

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Hence The equation to represent the rate of receding water level is                L = 34 (0.5)^{d}   . Answer

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Answer:

\boxed{\dfrac{y}{x}}

Step-by-step explanation:

\dfrac{\dfrac{1}{x} }{\dfrac{1}{y} } \ \text{can also be written as} \ \dfrac{1}{x} \div \dfrac{1}{y}

-------------------------------------------

\rightarrow \dfrac{1}{x} \div \dfrac{1}{y}

<u>Simplifying the expression using "a ÷ b = a x 1/b"</u>

\rightarrow \dfrac{1}{x} \times y

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Answer:

"Big Game's competitive footballs are the exact dimensions set down by the NCAA – approximately 10.5 to 11.5 inches in length, with a circumference of roughly 28 inches on the long side of the ball and 21 inches on the short side."

Step-by-step explanation:

Hope this helps

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