The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
<h3>What is a factor?</h3>
A factor of n is a number which when multiplied by another number gives us the number n.
In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,

Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as

Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
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Answer:
5x+3y, when x=4 and y= -3
5(4)+3(-3)=
20+ (-9)=
11
Step-by-step explanation:
Hope this helps. :)
X² - 3x - 10
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>
To find the perpendicular line a y- 2 = 7/3 (x + 5) you must first observe that the slope is m = 7/3, therefore, the slope of the perpendicular line put of the reciprocal, that is, m = - 3/7. So the possible options are A or C, but since the point (-4, 9) must go through the line, we find that the equation that satisfies that is option C.Therefore the perpendicular line that passes through the point (-4, 9) is C. y - 9 = -3/7 (x + 4)