Exercise
1 answer:
You might be interested in
The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
<h3>What is a factor?</h3>A factor of n is a number which when multiplied by another number gives us the number n.
In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,
Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as
Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
Learn more about Factors:
X² - 3x - 10
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>