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bija089 [108]
3 years ago
11

The odds of selecting a red card from a box of cards are 2:5. What is the probability of not selecting a red card from a box?

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
3:5 because if there's a 2:5 chance of grabbing a red card then just subtract 2 from 5 and you get 3:5
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dimulka [17.4K]
That should be 5 2/3 qt.
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He variable y is directly proportional to the variable x . If y = 10 when x = 6, what is the value of y when x = 15?
Delicious77 [7]

Answer:

B. 25

Step-by-step explanation:

10+6=16

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Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

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We average the 2nd and 3rd term:

(22 + 23) / 2

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B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

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IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
Find the area of the polygon.
zalisa [80]

Answer:

A=128\ cm^2

Step-by-step explanation:

we know that

The area of the polygon is equal to the area of a square plus the area of four congruent triangles

so

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where

b=8\ cm\\h=4\ cm

substitute

A=8^2+4[\frac{1}{2}(8)(4)]

A=64+64=128\ cm^2

4 0
3 years ago
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