t When you reverse the digitals in a certain number you increase its value by 27. Find the number if the sum fixes digits is 9.
1 answer:
The number=10x+y
we suggest this system of equations:
(10y+x)-(10x+y)=27
x+y=9 ⇒x=9-y
Can solve this system of equations by susbstitution method.
(10y+(9-y)-(10(9-y)+y)=27
10y+9-y-(90-10y+y)=27
10y-y+10y-y=27-9+90
18y=108
y=108/18
y=6
x=9-y
x=9-6
x=3
The number=10x+y=10(3)+6=36
Answer: the number is 36.
to check:
63-36=27
6+3=9
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1) There are 3 significant digits
2)
15 Mi/h = 22 ft/s
3)
4)
There are 4 significant digitis. Leter C
Answer:
x^2 + 10x + 25
Step-by-step explanation:
(B/2) ^2
10/2 = 5
5^2 = 25
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13
sina=3/√13, cosa=2/√13, tana=3/2
Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13
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