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mario62 [17]
3 years ago
12

Please do the questions that aren't answered! Show work!!

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
4) 0=-5n-2n
0=-7n
n=0
5) 6r-1+6r=11
12r-1+11
12r=12
r=1
6) r+11+8r=29
9r=18
r=2
7) -10=-14v+14v
-10=0
no solution because the sides are not equal
10) a-2+3=-2
a+1=-2
a=-3
11) 18=3(3x-6)
18=9x-18
36=9x
9x=36
x=4

hope i could help
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A scale drawing of a rectangular park had a scale of 1 cm = 100 m.
Brilliant_brown [7]

Answer:

521,400 meters squared

Step-by-step explanation:

With the 1cm = 100m scale

6.6 cm = 660m

7.9 cm = 790m

Area = 660 x 790 = 521,400 meters squared

7 0
3 years ago
I just need to know how to do this. pls help me
Vlada [557]
Vertically opposite angles are equal
With this information we can form an equation

2x+14=60
Subtract 14 from both sides
2x=46
Divide both sides by 2
X=23

x = 23 degrees
5 0
4 years ago
Read 2 more answers
Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).
BabaBlast [244]

Answer:

1241

Step-by-step explanation:

∴

L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

∴

the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.

7 0
1 year ago
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
What is the value of k if the line 5x+ky=12 passes through the point (2,-1).
olchik [2.2K]

Answer:

k = -2

Step-by-step explanation:

1. Substitute the point (2,-1) into the given equation 5x+ky=12. The first number is 2, the x-value. The second number is -1, the y-value.

5x + ky = 12

5(2) + k(-1) = 12

2. Simplify

5(2) + k(-1) = 12

10 + (-k) = 12

10 - k = 12

2. Isolate k

10 - k = 12

-k = 12-10

-k = 2   <= here multiply both sides by (-1)

k = -2

5 0
3 years ago
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