On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axi
s at (negative 3.4, 0), (3.9, 0), and (6, 0), and crosses the y-axis at (0, 25). Which statement is true about the local minimum of the graphed function?
2 answers:
Answer:
<u>The true statement is D</u>
Step-by-step explanation:
The rest of the question is the attached figure and the statement options.
- A. Over the interval [–4, –2], the local minimum is 0.
- B. Over the interval [–2, –1], the local minimum is 25.
- C. Over the interval [–1, 4], the local minimum is 0.
- D. Over the interval [4, 7], the local minimum is -7.
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According to the graph, we will check the options:
A. Over the interval [–4, –2], the local minimum is 0. (<u>Wrong</u>)
Because the minimum is -12
B. Over the interval [–2, –1], the local minimum is 25. (<u>Wrong</u>)
Because the minimum is 18
C. Over the interval [–1, 4], the local minimum is 0. (<u>Wrong</u>)
Because the minimum is at x = 4 less than zero
D. Over the interval [4, 7], the local minimum is -7. (<u>True</u>)
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Answer:
Volume of the cone = 130.83 cubic units
Step-by-step explanation:
The question us incomplete without the diagram of the cone and it's dimensions as this would enable us get the exact answer.
Find attached the diagram used in solving the solution.
Volume of cone = ⅓ πr²h
Radius = r = 5 unit
Height = h = 5 unit
π = 3.14
By inserting the values of each variables, we have:
Volume of cone = ⅓ × 3.14× (5)² × 5
= ⅓ × 3.14× 25×5 = ⅓ × 3.14×125
Volume of cone = (392.5)/3
Volume of cone = 130.8333
Volume of cone = 130.83 cubic units (to the nearest hundredth)
Volume of cone = 130.83 unit³
Answer:
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Step-by-step explanation:
