On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axi
s at (negative 3.4, 0), (3.9, 0), and (6, 0), and crosses the y-axis at (0, 25). Which statement is true about the local minimum of the graphed function?
2 answers:
Answer:
<u>The true statement is D</u>
Step-by-step explanation:
The rest of the question is the attached figure and the statement options.
- A. Over the interval [–4, –2], the local minimum is 0.
- B. Over the interval [–2, –1], the local minimum is 25.
- C. Over the interval [–1, 4], the local minimum is 0.
- D. Over the interval [4, 7], the local minimum is -7.
============================================================
According to the graph, we will check the options:
A. Over the interval [–4, –2], the local minimum is 0. (<u>Wrong</u>)
Because the minimum is -12
B. Over the interval [–2, –1], the local minimum is 25. (<u>Wrong</u>)
Because the minimum is 18
C. Over the interval [–1, 4], the local minimum is 0. (<u>Wrong</u>)
Because the minimum is at x = 4 less than zero
D. Over the interval [4, 7], the local minimum is -7. (<u>True</u>)
You might be interested in
Use the product rule first:
Use the chain rule to compute the derivative of . Let
and take
, so that by the chain rule
So we have
You can rewrite this a bit by factoring , just to make it look neater: