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vovikov84 [41]
3 years ago
6

On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axi

s at (negative 3.4, 0), (3.9, 0), and (6, 0), and crosses the y-axis at (0, 25). Which statement is true about the local minimum of the graphed function?

Mathematics
2 answers:
liubo4ka [24]3 years ago
5 0

Answer:

<u>The true statement is D</u>

Step-by-step explanation:

The rest of the question is the attached figure and the statement options.

  • A. Over the interval [–4, –2], the local minimum is 0.
  • B. Over the interval [–2, –1], the local minimum is 25.
  • C. Over the interval [–1, 4], the local minimum is 0.
  • D. Over the interval [4, 7], the local minimum is -7.

============================================================

According to the graph, we will check the options:

A. Over the interval [–4, –2], the local minimum is 0.  (<u>Wrong</u>)

Because the minimum is -12

B. Over the interval [–2, –1], the local minimum is 25.   (<u>Wrong</u>)

Because the minimum is 18

C. Over the interval [–1, 4], the local minimum is 0.  (<u>Wrong</u>)

Because the minimum is at x = 4 less than zero

D. Over the interval [4, 7], the local minimum is -7.    (<u>True</u>)

leonid [27]3 years ago
5 0

Answer:

d

Step-by-step explanation:

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Anit [1.1K]

The container has a total of 41 possible numbers from which to draw, and so each one as a probability of \dfrac1{41} of being drawn.

Most of these numbers are even (21 of them) and

P(\text{even})=\dfrac{21}{41}

20 of these numbers are greater than 30, so

P(\text{greater than 30})=\dfrac{20}{41}

and among these, exactly half are even, so that

P(\text{greater than 30 AND even})=\dfrac{10}{41}

So we have

P(\text{greater than 30}\mid\text{even})=\dfrac{P(\text{greater than 30 AND even})}{P(\text{even})}=\dfrac{\frac{10}{41}}{\frac{21}{41}}=\dfrac{10}{21}\approx0.48

7 0
2 years ago
Prove: <img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bb%7D" id="TexFormula1" title="\frac{a}{b}" alt="\frac{a}{b}" align="ab
Masteriza [31]

Step-by-step explanation:

\dfrac{a}{b} = \dfrac{c}{d}

Add 1 to both sides of the equation:

\dfrac{a}{b} + 1 = \dfrac{c}{d} + 1

Note that

\dfrac{a}{b} + 1 = \dfrac{a + b}{b}

Likewise,

\dfrac{c}{d} + 1 = \dfrac{c + d}{d}

Therefore,

\dfrac{a + b}{b} = \dfrac{c + d}{d}

8 0
2 years ago
Evaluate the function when x= -3, 0,and 4<br><img src="https://tex.z-dn.net/?f=h%28x%29%20%3D%20%20-%2010x" id="TexFormula1" tit
Nesterboy [21]
X = -3, 0, 4

h(x) = -10x     just plug in what x equals
h(-3) = -10(-3)
h(-3) = 30

h(x) = -10x
h(0) = -10(0)
h(0) = 0

h(x) = -10x
h(4) = -10(4)
h(4) = -40

v(x) = 14 - 3x
v(-3) = 14 - 3(-3)
v(-3) = 23

v(x) = 14 - 3x
v(0) = 14 - 3(0)
v(0) = 14

v(x) = 14 - 3x
v(4) = 14 - 3(4)
v(4) = 2

hope this is what they're asking for. hope this helps, God bless!
8 0
3 years ago
To solve the equation 4-3x2 - 7x=0 using the quadratic formula, what are the values of a, b, and c?
mafiozo [28]
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3 years ago
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Vsevolod [243]

Answer:7m = 7m

Step-by-step explanation:

3 0
3 years ago
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