Answer:
Expression is 8(n+2)
Step-by-step explanation:
smallest of 4 consecutive odd numbers =2n + 1
consecutive odd integers are found by adding 2 to the any given odd numbers
Thus, 2nd consecutive odd integers = 2n + 1 + 2 = 2n + 3
3rd consecutive odd integers = 2n + 3 + 2 = 2n + 5
2nd consecutive odd integers = 2n + 5 + 2 = 2n + 7
Thus, 4 consecutive odd integers are
2n + 1 ,2n + 3,2n + 5,2n + 7
sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16
sum of these numbers are = 8(n+2)
Thus, we see that the sum of numbers are 8(n+2)
As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .
thus expression is 8(n+2)
