As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
Answer:
Step-by-step explanation:
Use the Pythagorean Theorem to find the zeros of 6x² - 9x - 6.
x = [9±√(9²-4(6)(-6))]/[2(6)] = [9±√225]/12 = [9±15]/12 = 2, -½
Answer:
40
Step-by-step explanation:
So split it into two shapes. Two rectangles.
Rectangle 1 = 4 * 5 = 20
Rectangle 2 = 2 * 10 = 20
20 + 20 = 40
I really don’t know I’m just tryna get answers bc I’m failing and stuff and I’m sorry but ima just eh
