Terri walked in her own 93rd percentile, while April swam in her own 99th percentile. April is off to a slightly better start.
Answer:
9. 66°
10. 44°
11. 
12. 
13. 27.3
14. 33.9
15. 22°
16. 24°
Step-by-step explanation:
9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:
120 + 80 = 200
360 - 200 = 160
12(5) + 6 = 66°
19(5) - 1 = 94°
94 + 66 = 160
10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:
68 x 2 = 136
180 - 136 = 44
11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:
a² + b² = c²
a² + 6² = 8²
a² + 36 = 64
a² = 28
a = 
a = 
12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:
a² + b² = c²
a² + 2² = 4²
a² + 4 = 16
a² = 12
a = 
a = 
13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:
Sin(47°) = 
x = 27.3
14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:
Tan(62°) = 
x = 33.9
15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:
cos(θ) = 52/56
θ = cos^-1 (0.93)
θ = 22°
16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:
sin(θ) = 4/10
θ = sin^-1 (0.4)
θ = 24°
Good luck!!
Count by 6 so 6×4 is 24 so 1/4
The graph that shows the solutions for the inequality, y > -1/3x + 1 is: C. Graph A.
<h3>How to Find the Graph of a Linear Inequality?</h3>
The inequality sign, ">" means that the graph of the inequality has a dashed line where the shaded part is above the boundary line and the boundary line is dashed or dotted. If "≥" is used, the boundary line would not be dashed or dotted and the shaded area would be above it.
On the other hand, "<" is used when the shaded area is below the boundary line and the boundary line is a dashed line. If "≤" was used, the boundary line won't be dashed or dotted, while the shaded area would be below the boundary line that is not dotted.
Given y > -1/3x + 1, the slope (m) = change in y / change in x is -1/3.
Graph A has a slope of -1/3 and the shaded part is above the boundary line.
Therefore, the graph that shows the solutions for y > -1/3x + 1 is: C. Graph A.
Learn more about inequality graph on:
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