<em>Train A = 214
</em>
<em>
Train B = 86</em>
<em>Hope I helped!!! ^^</em>
<em>_______________</em>
<em>列車A = 214
</em>
<em>
列車B = 86
</em>
<em>私が助けてくれたらいいのに!^ ^</em>
Answer:
a = 4
Step-by-step explanation:



hypotenuse = a
opposite = 2√3
adjacent = b
theta = 60°
the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a




Answer:
46 terms
Step-by-step explanation:
a₁=b, a₂₁= bₙ, d₁=9, d₂=4
n=?
---------------
a₂₁= a₁+20d₁= a₁+20*9= a₁+180
bₙ= b₁+(n-1)d₂= a₁+4(n-1)
a₁+4(n-1)=a₁+180
4(n-1)=180
n-1= 180/4
n-1= 45
n=46
Given:
A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.
To find:
The coordinates of that point.
Solution:
Section formula: If point divides a line segment in m:n, then the coordinates of that point are

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get




Therefore, the coordinates of the required point are (0,3).