Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
<em>Jack scored a total of -40</em>
Step-by-step explanation:
<u>Arithmetic</u>
Jack took a test where the correct answers are given as positive numbers and the incorrect answers are negative numbers.
The scores were
-65,-10,-15,20,30
The total score is the arithmetic sum of all scores, including their signs:
Total score: -65-10-15+20+30
Total score: -40
Jack scored a total of -40
Answer: is not / is one x-value
Step-by-step explanation:
If R is the midpoint of PS, then PR = RS -- (1)
Also, PR + RS = PS -- (2)
__________________
PR + RS = PS
7x + 23 + 13x - 19 = PS
__________________
Now, PR = PS
7x + 23 = 13x - 19
7x - 13x = -19 - 23
-6x = -42
x = -42/-6
x = 7
__________________
PS = 7x + 23 + 13x - 19
PS = 7(7) + 23 + 13(7) - 19
PS = 49 + 23 + 91 - 19
<u>PS </u><u>=</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u>
Hope it helps!
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
Answer:
C(t)=5000 -10t
Step-by-step explanation:
There are many examples in the real world of relationships that are functions.
For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.
If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:
Where:
C (t): Amount of water in the tank as a function of time
: Initial amount of water in the tank at time t = 0
a: amount of water lost per hour
t: time in hours
Then the equation is:
The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.
Its domain is the set of all positive real numbers t between [0,500]
Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty
Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres
