Answer:
you can simply describe a formula as being a variable and an expression separated by an equal sign between them. In other words a formula is the same as an equation.
Step-by-step explanation:
Begin by subtracting the number that's being added to 4y. What you'll need to do now is divide the 4 into both side of the equation. default, it gives you the result as a whole number followed by a decimal with numbers after the decimal.
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
Answer:
1) The graph is as shown at the attached figure.
2) The line passes with (1,-3) and (2,-2)
Step-by-step explanation:
graph the line that passes with (3,-1) and has a y-intercept of -4
y-intercept is the value of y when x = 0
So, the line passes with (0 , -4)
The general form of the line y = mx + c
Where m is the slope and c is y-intercept
given y-intercept = -4 ⇒ ∴ c = -4
using the other point to find m
So, when x = 3 , y = -1
So, -1 = 3m - 4
Solve for m
3m = -1 + 4 = 3
m= 3/3 = 1
So, the equation of the line ⇒ <u>y = x - 4</u>
See the attached figure which represents the graph of the line
As shown at the graph the line passes through the points <u>(1,-3) and (2,-2)</u>
The function is in polar coordinates.
When this is the case, to pass to rectagular (cartesian) coordinates you use:
x = r cos(theta)
y = r sin(theta)
Then,
x = [2cos(theta) + 2sin(theta)]cos(theta) =
= 2 [cos(theta)]^2 + 2sin(theta)cos(theta) = 2 [cos(theta)]^2 + sin(2theta)
y = [2cos(theta) + 2sin(theta)]sin(theta) =
= 2 cos(theta)sin(theta) + 2[sin(theta)]^2 = sin(2theta) + 2[sin(theta)]^2
12 - (-2) (-4)
-2 * -4 = ?
A negative times a negative equals a positive value.
-2*-4 = 8
12 - 8 = ?
12-8 = 4
Because 4+8 = 12
Final answer: 4
