<span>To do that, you need to set it all to zero and factor:
x^2+8x+15 = 0
(x+5)(x+3) = 0
then put both those in parentheses chunks in their own equations
x + 5 = 0
x + 3 = 0
and then simplify
x = -5
x = -3
So the two points where the parabola crosses the x-axis are -5 and -3.</span>
Answer:
2<x<8
Here is the answer to he above question you asked. (I have to type at least 20 words to post my answer...)
The first one is 10.5
The second is y10
And the third is 7
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point (0, -4)
Point (-8, 0)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:

- Add/Subtract:

- Simplify:

Answer:
Step-by-step explanation:
C